Optimal. Leaf size=212 \[ \frac {2 (5 A+7 C) \sqrt {\cos (c+d x)} F\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{21 b^2 d \sqrt {b \cos (c+d x)}}+\frac {2 (5 A+7 C) \sin (c+d x)}{21 b d (b \cos (c+d x))^{3/2}}+\frac {2 A b \sin (c+d x)}{7 d (b \cos (c+d x))^{7/2}}-\frac {6 B E\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \sqrt {b \cos (c+d x)}}{5 b^3 d \sqrt {\cos (c+d x)}}+\frac {6 B \sin (c+d x)}{5 b^2 d \sqrt {b \cos (c+d x)}}+\frac {2 B \sin (c+d x)}{5 d (b \cos (c+d x))^{5/2}} \]
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Rubi [A] time = 0.27, antiderivative size = 212, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 8, integrand size = 41, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.195, Rules used = {16, 3021, 2748, 2636, 2640, 2639, 2642, 2641} \[ \frac {2 (5 A+7 C) \sqrt {\cos (c+d x)} F\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{21 b^2 d \sqrt {b \cos (c+d x)}}+\frac {2 (5 A+7 C) \sin (c+d x)}{21 b d (b \cos (c+d x))^{3/2}}+\frac {2 A b \sin (c+d x)}{7 d (b \cos (c+d x))^{7/2}}+\frac {6 B \sin (c+d x)}{5 b^2 d \sqrt {b \cos (c+d x)}}-\frac {6 B E\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \sqrt {b \cos (c+d x)}}{5 b^3 d \sqrt {\cos (c+d x)}}+\frac {2 B \sin (c+d x)}{5 d (b \cos (c+d x))^{5/2}} \]
Antiderivative was successfully verified.
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Rule 16
Rule 2636
Rule 2639
Rule 2640
Rule 2641
Rule 2642
Rule 2748
Rule 3021
Rubi steps
\begin {align*} \int \frac {\left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \sec ^2(c+d x)}{(b \cos (c+d x))^{5/2}} \, dx &=b^2 \int \frac {A+B \cos (c+d x)+C \cos ^2(c+d x)}{(b \cos (c+d x))^{9/2}} \, dx\\ &=\frac {2 A b \sin (c+d x)}{7 d (b \cos (c+d x))^{7/2}}+\frac {2 \int \frac {\frac {7 b^2 B}{2}+\frac {1}{2} b^2 (5 A+7 C) \cos (c+d x)}{(b \cos (c+d x))^{7/2}} \, dx}{7 b}\\ &=\frac {2 A b \sin (c+d x)}{7 d (b \cos (c+d x))^{7/2}}+(b B) \int \frac {1}{(b \cos (c+d x))^{7/2}} \, dx+\frac {1}{7} (5 A+7 C) \int \frac {1}{(b \cos (c+d x))^{5/2}} \, dx\\ &=\frac {2 A b \sin (c+d x)}{7 d (b \cos (c+d x))^{7/2}}+\frac {2 B \sin (c+d x)}{5 d (b \cos (c+d x))^{5/2}}+\frac {2 (5 A+7 C) \sin (c+d x)}{21 b d (b \cos (c+d x))^{3/2}}+\frac {(3 B) \int \frac {1}{(b \cos (c+d x))^{3/2}} \, dx}{5 b}+\frac {(5 A+7 C) \int \frac {1}{\sqrt {b \cos (c+d x)}} \, dx}{21 b^2}\\ &=\frac {2 A b \sin (c+d x)}{7 d (b \cos (c+d x))^{7/2}}+\frac {2 B \sin (c+d x)}{5 d (b \cos (c+d x))^{5/2}}+\frac {2 (5 A+7 C) \sin (c+d x)}{21 b d (b \cos (c+d x))^{3/2}}+\frac {6 B \sin (c+d x)}{5 b^2 d \sqrt {b \cos (c+d x)}}-\frac {(3 B) \int \sqrt {b \cos (c+d x)} \, dx}{5 b^3}+\frac {\left ((5 A+7 C) \sqrt {\cos (c+d x)}\right ) \int \frac {1}{\sqrt {\cos (c+d x)}} \, dx}{21 b^2 \sqrt {b \cos (c+d x)}}\\ &=\frac {2 (5 A+7 C) \sqrt {\cos (c+d x)} F\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{21 b^2 d \sqrt {b \cos (c+d x)}}+\frac {2 A b \sin (c+d x)}{7 d (b \cos (c+d x))^{7/2}}+\frac {2 B \sin (c+d x)}{5 d (b \cos (c+d x))^{5/2}}+\frac {2 (5 A+7 C) \sin (c+d x)}{21 b d (b \cos (c+d x))^{3/2}}+\frac {6 B \sin (c+d x)}{5 b^2 d \sqrt {b \cos (c+d x)}}-\frac {\left (3 B \sqrt {b \cos (c+d x)}\right ) \int \sqrt {\cos (c+d x)} \, dx}{5 b^3 \sqrt {\cos (c+d x)}}\\ &=-\frac {6 B \sqrt {b \cos (c+d x)} E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{5 b^3 d \sqrt {\cos (c+d x)}}+\frac {2 (5 A+7 C) \sqrt {\cos (c+d x)} F\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{21 b^2 d \sqrt {b \cos (c+d x)}}+\frac {2 A b \sin (c+d x)}{7 d (b \cos (c+d x))^{7/2}}+\frac {2 B \sin (c+d x)}{5 d (b \cos (c+d x))^{5/2}}+\frac {2 (5 A+7 C) \sin (c+d x)}{21 b d (b \cos (c+d x))^{3/2}}+\frac {6 B \sin (c+d x)}{5 b^2 d \sqrt {b \cos (c+d x)}}\\ \end {align*}
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Mathematica [A] time = 0.46, size = 136, normalized size = 0.64 \[ \frac {2 \left (5 (5 A+7 C) \sqrt {\cos (c+d x)} F\left (\left .\frac {1}{2} (c+d x)\right |2\right )+25 A \tan (c+d x)+15 A \tan (c+d x) \sec ^2(c+d x)+63 B \sin (c+d x)-63 B \sqrt {\cos (c+d x)} E\left (\left .\frac {1}{2} (c+d x)\right |2\right )+21 B \tan (c+d x) \sec (c+d x)+35 C \tan (c+d x)\right )}{105 b^2 d \sqrt {b \cos (c+d x)}} \]
Antiderivative was successfully verified.
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fricas [F] time = 1.42, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (C \cos \left (d x + c\right )^{2} + B \cos \left (d x + c\right ) + A\right )} \sqrt {b \cos \left (d x + c\right )} \sec \left (d x + c\right )^{2}}{b^{3} \cos \left (d x + c\right )^{3}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (C \cos \left (d x + c\right )^{2} + B \cos \left (d x + c\right ) + A\right )} \sec \left (d x + c\right )^{2}}{\left (b \cos \left (d x + c\right )\right )^{\frac {5}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 4.81, size = 729, normalized size = 3.44 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (C \cos \left (d x + c\right )^{2} + B \cos \left (d x + c\right ) + A\right )} \sec \left (d x + c\right )^{2}}{\left (b \cos \left (d x + c\right )\right )^{\frac {5}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {C\,{\cos \left (c+d\,x\right )}^2+B\,\cos \left (c+d\,x\right )+A}{{\cos \left (c+d\,x\right )}^2\,{\left (b\,\cos \left (c+d\,x\right )\right )}^{5/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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